b) Identify and write out all redox couples in reaction. Oxidation number of S=+6. So, SO42- can be dealt with on its own. Pb +2 S -2 + H +1 2 O -1 2 → Pb +2 S +6 O … Oxidation number pbso4 Therefore, the oxidation number of S in PbSO4 is +6. The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Therefore oxidation number of Pb is +2. Pb in PbSO4 : +2. Sum of all oxidation number =0. Since the ion has a -2 charge, the oxidation state of sulfur must be +6. Within the sulfate ion, each oxygen does have a -2 oxidation state. You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. Within polyatomic ions, you can frequently have oxidation states that are not "normal". PbSO4 --> Pb2+ + SO4 2- (A net dissociation reaction of the salt) SO4 has an oxidation number of -2. What is the oxidation number of phosphorous in the H3PO2 molecule? How to calculate oxidation number of Pb in PbSO4?And Explain? If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. Thank me later Shaawana is waiting for your help. D. none of these. Nice I mean I kinda said the answer in his question Pb PbO2 PbSO4 H2O H2SO4. Conversion of P b S O 4 to P b S is : A. reduction of S. B. oxidation of S. C. dissociation. Pb +2 S-2 + H +1 2 O-1 2 → Pb +2 S +6 O-2 4 + H +1 2 O-2 . Now, since O is always -2, the S must be +6 to make the whole compound zero. Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Which substance is the reducing agent in the following reaction? Conversion of PbSO4 to PbS ... chemistry. Therefore x+6-8=0. Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) → 2PbSO 4 (s) + 2H 2 O(l) Add your answer and earn points. H in H2 : 0. Oxidation number of Pb is +2 THat leaves, though, the oxidation state of Pb to be +2. Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers). It is suggested that a precipitation mechanism to form PbSO 4 occurs under some conditions prior to the solid state … The system is compared with measurements on Pb(Hg) in H 2 SO 4 and with Pb(Hg), Hg, solid Pb in HClO 4 solution. gsplcu gsplcu Answer: The central atom is S. Explanation: Look at the structure. MEDIUM. +1 +3 0-1 +2 +1. Expert Answer: Let the oxidation number of Pb=x. H2O2 + PbS --> PbSO4 + H2O. For a simple ion, like Pb in PbSO4, it is the same as the ionic charge, ie +2. 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